SQR - mkilgore/QB64pe GitHub Wiki
The SQR function returns the square root of a numerical value.
- square_root = SQR(value)
- The square root returned is normally a SINGLE or DOUBLE numerical value.
- The value parameter can be any positive numerical type. Negative parameter values will not work!
- Other exponential root functions can use fractional exponents(^) enclosed in parenthesis only. EX: root = c ^ (a / b)
'' '' A% = 3: B% = 4 PRINT "hypotenuse! ="; SQR((A% ^ 2) + (B% ^ 2)) '' '' |
hypotenuse = 5 |
Example 2: Finding the Cube root of a number.
'' '' number = 8 cuberoot = number ^ (1/3) PRINT cuberoot '' '' |
2 |
Example 3: Negative roots return fractional values of one.
'' '' number = 8 negroot = number ^ -2 PRINT negroot '' '' |
.015625 |
- Explanation: A negative root means that the exponent value is actually inverted to a fraction of 1. So x ^ -2 actually means the result will be: 1 / (x ^ 2).
DEFLNG P
DO
PRIME = -1 'set PRIME as True
INPUT "Enter any number to check up to 2 million (Enter quits): ", guess$
PR = VAL(guess$)
IF PR MOD 2 THEN 'check for even number
FOR P = 3 TO SQR(PR) STEP 2 'largest number that could be a multiple is the SQR
IF PR MOD P = 0 THEN PRIME = 0: EXIT FOR 'MOD = 0 when evenly divisible by another
NEXT
ELSE : PRIME = 0 'number to be checked is even so it cannot be a prime
END IF
IF PR = 2 THEN PRIME = -1 '2 is the ONLY even prime
IF PR = 1 THEN PRIME = 0 'MOD returns true but 1 is not a prime by definition
IF PRIME THEN PRINT "PRIME! How'd you find me? " ELSE PRINT "Not a prime, you lose!"
LOOP UNTIL PR = 0 '' ''
|
Enter any number to check up to 2 million (Enter quits): 12379 PRIME! How'd you find me? |
See also:
- MOD (integer remainder division)
- ^ (exponential operator)
- Mathematical Operations
- Derived Trigonometric Functions
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