0384. Shuffle an Array - kumaeki/LeetCode GitHub Wiki
Given an integer array nums, design an algorithm to randomly shuffle the array. All permutations of the array should be equally likely as a result of the shuffling.
Implement the Solution class:
- Solution(int[] nums) Initializes the object with the integer array nums.
- int[] reset() Resets the array to its original configuration and returns it.
- int[] shuffle() Returns a random shuffling of the array.
Example 1:
Input
["Solution", "shuffle", "reset", "shuffle"]
[[1, 2, 3](/kumaeki/LeetCode/wiki/[1,-2,-3), [], [], []]
Output
[null, [3, 1, 2], [1, 2, 3], [1, 3, 2]]
Explanation
Solution solution = new Solution([1, 2, 3]);
solution.shuffle(); // Shuffle the array [1,2,3] and return its result.
// Any permutation of [1,2,3] must be equally likely to be returned.
// Example: return [3, 1, 2]
solution.reset(); // Resets the array back to its original configuration [1,2,3]. Return [1, 2, 3]
solution.shuffle(); // Returns the random shuffling of array [1,2,3]. Example: return [1, 3, 2]
Constraints:
- 1 <= nums.length <= 200
- -10^6 <= nums[i] <= 10^6
- All the elements of nums are unique.
- At most 5 * 10^4 calls in total will be made to reset and shuffle.
解法1
需要打乱顺序时, 遍历每个元素, 随机和数组中的某个元素交换位置(包括它自己).
class Solution {
int[] original;
int[] res;
Random ran;
public Solution(int[] nums) {
original = nums;
res = nums.clone();
ran = new Random();
}
/** Resets the array to its original configuration and return it. */
public int[] reset() {
res = original.clone();
return res;
}
/** Returns a random shuffling of the array. */
public int[] shuffle() {
for(int i = 0, len = res.length; i < len - 1; i++)
swap(res, i, i + ran.nextInt(len - i));
return res;
}
private void swap(int[] arr, int i, int j){
int temp = arr[i];
arr[i] = arr[j];
arr[j] = temp;
}
}
/**
* Your Solution object will be instantiated and called as such:
* Solution obj = new Solution(nums);
* int[] param_1 = obj.reset();
* int[] param_2 = obj.shuffle();
*/