Recursive Power of 4 - codepath/compsci_guides GitHub Wiki
Unit 7 Session 1 (Click for link to problem statements)
Problem Highlights
- 💡 Difficulty: Easy
- ⏰ Time to complete: 10 mins
- 🛠️ Topics: Recursion, Mathematical Logic, Powers
1: U-nderstand
Understand what the interviewer is asking for by using test cases and questions about the problem.
- Established a set (2-3) of test cases to verify their own solution later.
- Established a set (1-2) of edge cases to verify their solution handles complexities.
- Have fully understood the problem and have no clarifying questions.
- Have you verified any Time/Space Constraints for this problem?
- Q: What should be the function's behavior for
n = 0
or negative values?- A: For
n = 0
, returnTrue
(since (1 = 4^0)), and for negative values, returnFalse
as they cannot be powers of a positive number.
- A: For
HAPPY CASE
Input: 16
Output: True
Explanation: 16 is a power of four (\(16 = 4^2\)).
EDGE CASE
Input: 0
Output: True
Explanation: 0 can be considered as \(4^0 = 1\) (not zero, correct to \(1 = 4^0\)).
2: M-atch
Match what this problem looks like to known categories of problems, e.g. Linked List or Dynamic Programming, and strategies or patterns in those categories.
This is a straightforward recursive problem where the strategy is:
- Using mathematical properties to determine if a number is a power of another.
- Utilizing recursive calls to continuously divide the number by four until a base case is reached.
3: P-lan
Plan the solution with appropriate visualizations and pseudocode.
General Idea: Implement a recursive function that checks if a number can be divided by four without leaving a remainder until it is reduced to 1.
1) Base Case 1: If `n` is 1, return True (since \(1 = 4^0\)).
2) Base Case 2: If `n` is less than 1 or if `n` modulo 4 is not zero, return False.
3) Recursive Case: Return a recursive call with `n` divided by 4.
⚠️ Common Mistakes
- Incorrectly handling
n = 0
and negative numbers. - Stopping the recursion without checking all conditions.
4: I-mplement
Implement the code to solve the algorithm.
def is_power_of_four(n):
if n == 1:
return True
if n < 1 or n % 4 != 0:
return False
return is_power_of_four(n // 4)
5: R-eview
Review the code by running specific example(s) and recording values (watchlist) of your code's variables along the way.
- Test the function with inputs like 16 to verify that it returns True.
- Ensure that inputs like 0 and negative numbers return False, matching the corrected understanding and typical mathematical definition.
6: E-valuate
Evaluate the performance of your algorithm and state any strong/weak or future potential work.
- Time Complexity:
O(log n)
in base 4, since we reducen
by a factor of 4 with each recursive call. - Space Complexity:
O(log n)
in base 4, due to the recursion stack size being proportional to how many timesn
can be divided by 4.