Minimum Number of Steps to Match Treasure Maps - codepath/compsci_guides GitHub Wiki
U-nderstand
Understand what the interviewer is asking for by using test cases and questions about the problem.
- Q
- What is the desired outcome?
- To determine the minimum number of steps needed to make
map2
an anagram ofmap1
.
- To determine the minimum number of steps needed to make
- What input is provided?
- Two strings,
map1
andmap2
, of the same length.
- Two strings,
- What is the desired outcome?
P-lan
Plan the solution with appropriate visualizations and pseudocode.
General Idea: Count the frequency of each character in both strings, then calculate how many characters in map2
need to be changed to match the character frequency in map1
.
1) Count the frequency of each character in `map1` and `map2`.
2) Initialize a variable `steps` to 0, which will count the minimum number of changes needed.
3) Iterate through the characters in `map2`:
- If a character exists in both `map1` and `map2` but `map2` has more occurrences, add the difference to `steps`.
- If a character exists in `map2` but not in `map1`, add the entire count of that character to `steps`.
4) Return the value of `steps`.
⚠️ Common Mistakes
- Forgetting to account for characters in
map2
that do not exist inmap1
. - Miscalculating the difference in character frequencies between the two maps.
I-mplement
def min_steps_to_match_maps(map1, map2):
# Step 1: Create frequency dictionaries for map1 and map2
count1 = {}
count2 = {}
for char in map1:
if char in count1:
count1[char] += 1
else:
count1[char] = 1
for char in map2:
if char in count2:
count2[char] += 1
else:
count2[char] = 1
# Step 2: Calculate the number of changes needed
steps = 0
# Step 3: Calculate the excess characters in map2 that are not in map1
for char in count2:
if char in count1:
if count2[char] > count1[char]:
steps += count2[char] - count1[char]
else:
steps += count2[char]
return steps