Find Missing - codepath/compsci_guides GitHub Wiki
Unit 7 Session 1 (Click for link to problem statements)
Problem Highlights
- 💡 Difficulty: Medium
- ⏰ Time to complete: 15 mins
- 🛠️ Topics: Binary Search, Arrays
1: U-nderstand
Understand what the interviewer is asking for by using test cases and questions about the problem.
- Established a set (2-3) of test cases to verify their own solution later.
- Established a set (1-2) of edge cases to verify their solution handles complexities.
- Have fully understood the problem and have no clarifying questions.
- Have you verified any Time/Space Constraints for this problem?
- Q: What happens if there are no missing numbers?
- A: If no numbers are missing, the missing number would logically be ( n ), since the numbers are from 0 to ( n-1 ).
HAPPY CASE
Input: nums = [0, 1, 3, 4, 5]
Output: 2
Explanation: The number 2 is missing in the sequence.
EDGE CASE
Input: nums = [0, 1, 2, 3, 4]
Output: 5
Explanation: Since no numbers are missing from 0 to 4, the missing number is 5.
2: M-atch
Match what this problem looks like to known categories of problems, e.g. Linked List or Dynamic Programming, and strategies or patterns in those categories.
This problem is a variant of the classic binary search:
- Adapting binary search to detect an inconsistency in an otherwise complete series of sequential numbers.
3: P-lan
Plan the solution with appropriate visualizations and pseudocode.
General Idea: Use binary search to efficiently find the missing number in a series that is nearly complete.
1) Establish binary search bounds with `left` at 0 and `right` at the last index of the array.
2) While `left` is less than `right`:
- Compute the middle index.
- If the element at the middle index matches the index, adjust `left` to `mid + 1`.
- Otherwise, adjust `right` to `mid`.
3) The missing number will be at the position indicated by `left` after the loop completes.
⚠️ Common Mistakes
- Not considering the possibility that the missing number could be at the very end of the sequence (i.e., ( n )).
4: I-mplement
Implement the code to solve the algorithm.
def find_missing(nums):
left, right = 0, len(nums)
while left < right:
mid = (left + right) // 2
if nums[mid] > mid:
right = mid
else:
left = mid + 1
return left
5: R-eview
Review the code by running specific example(s) and recording values (watchlist) of your code's variables along the way.
- Test with input [0, 1, 3, 4, 5] to confirm it finds the missing number 2.
- Check with input [0, 1, 2, 3, 4] to ensure it returns 5, demonstrating that it correctly identifies the next logical missing number.
6: E-valuate
Evaluate the performance of your algorithm and state any strong/weak or future potential work.
- Time Complexity:
O(log n)
because each iteration of the loop narrows the search space by half. - Space Complexity:
O(1)
as the space used does not scale with the size of the input.