Count Even Strings - codepath/compsci_guides GitHub Wiki
TIP102 Unit 1 Session 2 Standard (Click for link to problem statements)
Problem Highlights
- 💡 Difficulty: Easy
- ⏰ Time to complete: 10 mins
- 🛠️ Topics: String Length, List Operations
U-nderstand
Understand what the interviewer is asking for by using test cases and questions about the problem.
- Established a set (2-3) of test cases to verify their own solution later.
- Established a set (1-2) of edge cases to verify their solution handles complexities.
- Have fully understood the problem and have no clarifying questions.
- Have you verified any Time/Space Constraints for this problem?
- The function
count_evens()
should take a list of strings lst and return the count of strings with even lengths.
HAPPY CASE
Input: lst = ["na", "nana", "nanana", "batman", "!"]
Expected Output: 4
Input: lst = ["you", "either", "die", "a", "hero", "or", "you", "live", "long", "enough", "to", "see", "yourself", "become", "the", "villain"]
Expected Output: 9
EDGE CASE
Input: lst = []
Expected Output: 0
P-lan
Plan the solution with appropriate visualizations and pseudocode.
General Idea: Iterate through the list of strings, check the length of each string, and count those with even lengths.
1. Define the function `count_evens(lst)`.
2. Initialize a counter variable `count` to 0.
3. Loop through each string in `lst`.
- If the length of the string is even, increment the `count` by 1.
4. Return the `count`
⚠️ Common Mistakes
- Forgetting to check the length correctly or initializing the count variable.
I-mplement
Implement the code to solve the algorithm.
def count_evens(lst):
count = 0
for string in lst:
if len(string) % 2 == 0:
count += 1
return count