Cook Off - codepath/compsci_guides GitHub Wiki
U-nderstand
Understand what the interviewer is asking for by using test cases and questions about the problem.
- Q:
- What is the desired outcome?
- To find the maximum number of copies of
target_meal
that can be created using the giveningredients
.
- To find the maximum number of copies of
- What is the desired outcome?
- Q:
- What input is provided?
- Two strings,
ingredients
andtarget_meal
.
- Two strings,
- What input is provided?
P-lan
Plan the solution with appropriate visualizations and pseudocode.
General Idea: Count the frequency of each character in ingredients
and target_meal
, then determine how many times target_meal
can be formed by dividing the counts.
1) Count the frequency of each character in `ingredients` and `target_meal`.
2) Initialize `max_copies` to infinity.
3) For each character in `target_meal`, check if it is present in `ingredients`.
- If not, return 0.
- Otherwise, update `max_copies` with the minimum value of the integer division of the counts.
4) Return `max_copies`.
⚠️ Common Mistakes
- Not correctly handling the case where a character in
target_meal
is missing fromingredients
.
I-mplement
def max_attempts(ingredients, target_meal):
# Step 1: Manually count the frequency of each character in ingredients
ingredients_count = {}
for char in ingredients:
if char in ingredients_count:
ingredients_count[char] += 1
else:
ingredients_count[char] = 1
# Step 2: Manually count the frequency of each character in target_meal
target_meal_count = {}
for char in target_meal:
if char in target_meal_count:
target_meal_count[char] += 1
else:
target_meal_count[char] = 1
max_copies = float('inf')
# Step 3: Calculate the maximum number of times the target meal can be made
for char in target_meal_count:
if char not in ingredients_count:
return 0
max_copies = min(max_copies, ingredients_count[char] // target_meal_count[char])
return max_copies