Bouncy Flouncy Trouncy Pouncy - codepath/compsci_guides GitHub Wiki
TIP102 Unit 1 Session 1 Advanced (Click for link to problem statements)
TIP102 Unit 1 Session 2 Standard (Click for link to problem statements)
Problem Highlights
- 💡 Difficulty: Easy
- ⏰ Time to complete: 5 mins
- 🛠️ Topics: Lists, Iteration, Conditionals
U-nderstand
Understand what the interviewer is asking for by using test cases and questions about the problem.
-
Q: What is the input to the function?
- A: The input is a list of strings
operations
where each string is either "bouncy", "flouncy", "trouncy", or "pouncy".
- A: The input is a list of strings
-
Q: What is the expected output of the function?
- A: The function should return the final value of the variable
tigger
after performing all the operations.
- A: The function should return the final value of the variable
-
Q: What are the initial conditions or constraints?
- A: Initially, the value of
tigger
is1
. The listoperations
can contain any number of strings, including none.
- A: Initially, the value of
-
Q: How should operations be interpreted?
- A: "bouncy" and "flouncy" increment the value of
tigger
by 1, while "trouncy" and "pouncy" decrement the value oftigger
by 1.
- A: "bouncy" and "flouncy" increment the value of
-
Q: What if the list is empty?
- A: If the list is empty, the value of
tigger
remains1
.
- A: If the list is empty, the value of
-
The function
final_value_after_operations()
should take a list of strings operations and return the final value of the variable tigger after performing all the operations. The initial value of tigger is 1.
HAPPY CASE
Input: operations = ["trouncy", "flouncy", "flouncy"]
Expected Output: 2
Explanation: The operations are performed as follows:
Initially, tigger = 1.
trouncy: tigger is decremented by 1, tigger = 0.
flouncy: tigger is incremented by 1, tigger = 1.
flouncy: tigger is incremented by 1, tigger = 2.
Input: operations = ["bouncy", "bouncy", "flouncy"]
Expected Output: 4
Explanation: The operations are performed as follows:
Initially, tigger = 1.
bouncy: tigger is incremented by 1, tigger = 2.
bouncy: tigger is incremented by 1, tigger = 3.
flouncy: tigger is incremented by 1, tigger = 4.
EDGE CASE
Input: operations = ["trouncy"]
Expected Output: 0
Explanation: The only operation decrements tigger to 0.
P-lan
Plan the solution with appropriate visualizations and pseudocode.
General Idea: Initialize tigger to 1, then iterate through the list of operations to modify tigger based on the operation type.
1. Define the function `final_value_after_operations(operations)`.
2. Initialize the variable `tigger` to 1.
3. Iterate through the list of `operations`.
4. For each operation:
- If it is "bouncy" or "flouncy", increment `tigger` by 1.
- If it is "trouncy" or "pouncy", decrement `tigger` by 1.
5. Return the final value of `tigger`.
⚠️ Common Mistakes
- Forgetting to account for all operation types.
- Not initializing tigger correctly.
I-mplement
Implement the code to solve the algorithm.
def final_value_after_operations(operations):
# Initialize tigger to 1
tigger = 1
# Iterate through the list of operations
for operation in operations:
if operation == "bouncy" or operation == "flouncy":
tigger += 1
elif operation == "trouncy" or operation == "pouncy":
tigger -= 1
# Return the final value of tigger
return tigger