47. Permutations II - cocoder39/coco39_LC GitHub Wiki
Notes 2020:
class Solution:
def permuteUnique(self, nums: List[int]) -> List[List[int]]:
counters = collections.Counter(nums)
res = []
self.backtrack(len(nums), counters, [], res)
return res
def backtrack(self, l, counters, path, res):
if len(path) == l:
res.append(path[:])
return
for num in counters:
if counters[num] > 0:
path.append(num)
counters[num] -= 1
self.backtrack(l, counters, path, res)
path.pop()
counters[num] += 1
Time complexity: O(N * N!) Same as permutations
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tricky is there are repeated elements, and the generated sequence should be unique.
- sorting can make repeated elements be next to each other.
- all unvisited element are candidates that can be put at this position. Among all those unvisited repeated elements, we choose only the first element.
t(n) = O(n) + n * t(n-1)
t(n-1) = O(n) + (n-1) * t(n-2)
thus t(n) > O(n!)
class Solution {
public:
vector<vector<int>> permuteUnique(vector<int>& nums) {
vector<vector<int>> res;
vector<int> cur;
vector<bool> visited(nums.size());
sort(nums.begin(), nums.end());
helper(res, cur, visited, nums);
return res;
}
private:
void helper(vector<vector<int>>& res, vector<int>& cur, vector<bool>& visited, vector<int>& nums) {
if (cur.size() == nums.size()) {
res.push_back(cur);
return;
}
for (int i = 0; i < nums.size(); i++) {
if (! visited[i]) {
//nums[i] and nums[i - 1] are racing only if they are equal and both are candidiates at current level
if (i > 0 && ! visited[i - 1] && nums[i] == nums[i - 1]) {
continue;
}
visited[i] = true;
cur.push_back(nums[i]);
helper(res, cur, visited, nums);
cur.pop_back();
visited[i] = false;
}
}
}
};