2024 07 17 issue with backspacing in web based tui solving cursor positioning challenge - bizkite-co/handterm GitHub Wiki
original file name: Codeium Chat - DK33x0hudI5ZaKUHHkmy7IFhNWyOH2Az.md
summary: The user is working on a web-based TUI using xterm.js
and is facing an issue with backspacing where they need to move to the end of the previous line before removing a character. They provided code that moves to the beginning of the previous line instead of the end. Codeium, a helper, suggested using specific escape sequences (\x1b[A
and \x1b[999C
) to move the cursor to the end of the previous line before deletion. After trying this, the user found that the last character of the previous line was not being deleted as expected, leading to a dangling character at the end of the line. Codeium explained this issue, particularly due to the cursor being positioned just before the last character and not directly on it. They recommended a revised approach, including inserting a space to overcome this limitation, but noted that a direct solution isn't simple with terminal escape sequences. They advised considering tracking line contents in the application logic for more precise control. Finally, the user sought help in implementing the recommendations within their existing code block for resolving the deletion issue. Codeium provided a revised code snippet with additional movement commands to position the cursor hopefully at the last character for deletion, acknowledging the complexity of achieving this behavior with standard ANSI escape sequences and xterm.js
capabilities.
date: 2024-07-17T11:29
Note: This is purely the output of the chat conversation and does not contain any raw data, codebase snippets, etc. used to generate the output.
User at 11:29 am, Jul 17, 2024
I am using xterm.js
in my web-based TUI.
When I backspace I want to remove the character I am backspacing over, and if I am at the begining of the second line or greater y-value lines, I want to move to the end of the previous line and remove the character there.
I have this, but it is moving to the begiinng of the previous line:
handleBackSpaceAndNavigation(data: string): boolean {
let result = false;
if (data.charCodeAt(0) === 127) {
if (this.isCursorOnPrompt()) return true;
this.tempPassword = this.tempPassword.slice(0, -1);
// If the y is greater than zero and the x is 0, move to the end of the previous line
if (this.terminal.buffer.active.cursorY > 0 && this.terminal.buffer.active.cursorX === 0) {
this.terminal.write('\x1b[F\x1b[P');
}
this.terminal.write('\x1b[D\x1b[P');
this.props.onRemoveCharacter(this.getCurrentCommand().slice(0,-1));
result = true;
}
return result;
}
Codeium at 11:29 am, Jul 17, 2024
In your handleBackSpaceAndNavigation
function, you correctly identified the need to move the cursor to the previous line when backspacing from the beginning of a line (when cursorY > 0
and cursorX === 0
). However, the escape sequence you are using, \x1b[F\x1b[P
, moves the cursor to the first position of the previous line but does not position it at the end of that line.
To move the cursor to the end of the previous line, you can use the following approach:
- Move the cursor up one line:
\x1b[A
- Move the cursor to the end of that line:
\x1b[999C
The escape sequence \x1b[A
moves the cursor up one line, and \x1b[999C
moves it to the right 999 positions, which effectively positions it at the end of the line since terminal lines won't be that long. This is a common hack to get to the end of the line because there isn't a standard ANSI escape sequence to directly move to the end of a line.
Here's how you can integrate this into your existing function:
handleBackSpaceAndNavigation(data: string): boolean {
let result = false;
if (data.charCodeAt(0) === 127) {
if (this.isCursorOnPrompt()) return true;
this.tempPassword = this.tempPassword.slice(0, -1);
// If the y is greater than zero and the x is 0, move to the end of the previous line
if (this.terminal.buffer.active.cursorY > 0 && this.terminal.buffer.active.cursorX === 0) {
// Move up one line and then to the end of that line
this.terminal.write('\x1b[A\x1b[999C');
}
// Move the cursor left one position and delete the character there
this.terminal.write('\x1b[D\x1b[P');
this.props.onRemoveCharacter(this.getCurrentCommand().slice(0,-1));
result = true;
}
return result;
}
This code moves the cursor to the correct position before deleting the character, which should achieve the behavior you're describing.
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User at 12:01 pm, Jul 17, 2024
That sort of works but it doesn't delete the last character of the previous line. It jumps to the second-to-last character and subsequent backspaces delete from there, leaving a dangling last-character at the end of the line.
Codeium at 12:01 pm, Jul 17, 2024
Given your description of the issue, it appears the cursor is indeed moving to the end of the previous line but not deleting the last character as intended because the deletion command executes before the cursor has effectively moved to the last character.
A straightforward approach to ensure the last character of the previous line is deleted involves adjusting the order of operations slightly. You should move the cursor to the end of the previous line and then issue a command to delete a character. However, since the cursor is moved to just before the last character with \x1b[A\x1b[999C
, you need an additional step to move the cursor right by one position before deleting.
Unfortunately, there's a misunderstanding in the initial solution's explanation. The sequence \x1b[999C
(move right) positions the cursor to the end, but to delete the last character, you must ensure the cursor is actually on the last character, then delete it.
A precise solution isn't straightforward without an additional move right, because after moving to the end with \x1b[999C
, you're positioned just before the last character, not on it. Since terminals commonly don't have a built-in command to delete the last character directly, you might need to ensure the character is replaced or effectively removed with a workaround.
Given the constraints of terminal control sequences, here's an alternative approach:
- After moving to the end of the previous line, insert a space (or another character) to ensure you can move onto what was the last character.
- Move back one character.
- Delete the character (now the second-to-last character due to the inserted space).
- Optionally, delete the inserted space if necessary.
However, this method may introduce unnecessary complexity for what should be a simpler task. A more direct approach would be to ensure that when you move to the end of the line, you correctly adjust the cursor to delete the character directly. Unfortunately, without a direct way to move the cursor onto the last character and delete it in one go, you're limited by the behavior of the terminal and the escape sequences available.
To address the immediate issue of not deleting the last character on the line, consider adjusting the logic that handles the movement and deletion to better fit the operational constraints of your terminal setup. You might need to experiment with the sequence of operations or even maintain a buffer of the line contents to more accurately control deletions.
If your goal remains to have a robust handling of backspace at the beginning of lines, it might be worth considering tracking the line content in your application logic, allowing you to more precisely manage cursor position and character deletion without relying solely on terminal escape sequences.
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User at 12:04 pm, Jul 17, 2024
How would you translate all that into this code block?
handleBackSpaceAndNavigation(data: string): boolean {
let result = false;
if (data.charCodeAt(0) === 127) {
if (this.isCursorOnPrompt()) return true;
this.tempPassword = this.tempPassword.slice(0, -1);
// If the y is greater than zero and the x is 0, move to the end of the previous line
if (this.terminal.buffer.active.cursorY > 0 && this.terminal.buffer.active.cursorX === 0) {
// Move up one line and then to the end of that line
this.terminal.write('\x1b[A\x1b[999C');
}
// Move the cursor left one position and delete the character there
this.terminal.write('\x1b[D\x1b[P');
this.props.onRemoveCharacter(this.getCurrentCommand().slice(0, -1));
result = true;
}
return result;
}
We can try different things to narrow down the best solution.
Codeium at 12:05 pm, Jul 17, 2024
To address the issue within your code block, we need to adjust the strategy slightly. Since directly moving to the end and deleting the last character isn't working as expected, let's focus on ensuring the cursor is positioned correctly for deletion.
Given the constraints and the goal to delete the last character of the previous line, you might need to slightly adjust your approach. Unfortunately, without direct support for "move to last character and delete," the terminal control sequences require us to be a bit creative.
Here's a revised approach:
- Move up one line:
\x1b[A
. - Move to the right far enough that you're likely at or past the end of the line:
\x1b[999C
. - Move back one character to ensure you're on the last character:
\x1b[D
. - Delete the character there:
\x1b[P
.
This sequence is built on the assumption that you're trying to delete the character at the end of the previous line when the cursor is at the beginning of the current line (x == 0
).
However, if the deletion of the last character from the previous line is not working as expected because the cursor isn't precisely on the last character, you might need a different approach, as most terminals don't have a built-in command to delete the last character directly without the cursor being right on it.
Given your description, it sounds like the terminal is behaving as if the cursor ends up before the last character, not on it, thereby not allowing the deletion of the actual last character.
Since the straightforward method isn't behaving as expected, and without additional commands to ensure deletion of the last character, you could:
- Ensure the line lengths are tracked so you can move the cursor directly to the last character before issuing a delete.
- Consider if there's a way to adjust the terminal's behavior or explore if
xterm.js
offers any additional APIs or plugins that handle this case more gracefully.
For now, let's refine the existing approach assuming the standard ANSI escape sequences and xterm.js
capabilities:
handleBackSpaceAndNavigation(data: string): boolean {
let result = false;
if (data.charCodeAt(0) === 127) {
if (this.isCursorOnPrompt()) return true;
this.tempPassword = this.tempPassword.slice(0, -1);
// If the y is greater than zero and the x is 0, move to the end of the previous line
if (this.terminal.buffer.active.cursorY > 0 && this.terminal.buffer.active.cursorX === 0) {
// Attempt to move up one line, to the right far enough, then back one, and delete
this.terminal.write('\x1b[A\x1b[999C\x1b[D\x1b[P');
} else {
// For all other cases, move the cursor left one position and delete the character there
this.terminal.write('\x1b[D\x1b[P');
}
this.props.onRemoveCharacter(this.getCurrentCommand().slice(0, -1));
result = true;
}
return result;
}
This revision attempts to incorporate the necessary adjustments directly into your provided code block. If this still does not behave as expected, further investigation into xterm.js
documentation or considering a managed approach to track and manipulate the command line buffer in your application logic may be required.
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