542_01Matrix - a920604a/leetcode GitHub Wiki
- bfs -> time out
class Solution {
public:
vector<vector<int>> updateMatrix(vector<vector<int>>& mat) {
// dfs seem not to work
int n = mat.size(), m = mat[0].size();
vector<vector<int>> ret(n, vector<int>(m, INT_MAX));
queue<vector<int>> q;
vector<int> d = {0,1,0,-1};
for(int i=0;i<n;++i){
for(int j =0;j<m;++j){
if(mat[i][j] == 0){
// bfs can find the shortest path
q.push({i,j});
int depth = 0;
vector<vector<bool>> visited(n, vector<bool>(m, false));
while(!q.empty()){
int size = q.size();
for(int _=0;_<size ; ++_){
vector<int> p = q.front();
q.pop();
int x = p[0], y=p[1];
if(x<0 || y<0 || x>n-1 || y>m-1 || visited[x][y]) continue;
visited[x][y] = true;
if(mat[x][y] ==1) {
ret[x][y] = min(ret[x][y], depth);
}
q.push({x-1, y});
q.push({x+1, y});
q.push({x, y-1});
q.push({x, y+1});
}
depth++;
}
ret[i][j] = 0;
}
}
}
return ret;
}
};
將 mat[i][j]=1
的地方先收集起來
ret[x][y] = 1 + ret[p[0]][p[1]];
class Solution {
public:
vector<vector<int>> updateMatrix(vector<vector<int>>& mat) {
int n = mat.size() , m=mat[0].size();
vector<vector<int>> ret = mat;
queue<vector<int>> q;
for(int i=0;i<n;++i){
for(int j = 0;j<m;++j){
if(mat[i][j] == 0) q.push({i,j});
else ret[i][j] = -1;
}
}
vector<vector<int>> dirs{{0,-1},{-1,0},{0,1},{1,0}};
while(!q.empty()){
vector<int> p = q.front();
q.pop();
for(auto d:dirs){
int x= p[0]+d[0], y = p[1] +d[1];
if(x<0 || y<0 || x>n-1 || y>m-1 || ret[x][y]!=-1) continue;
// 記住父節點,並從他出發
ret[x][y] = 1+ ret[p[0]][p[1]];
q.push({x,y});
}
}
return ret;
}
};