title: 224. Basic Calculator
tags:
- Math
categories: leetcode
comments: false
class Solution {
public:
int calculate(string s) {
stack<int> sta;
int res = 0;
int sign = 1;
int n = s.size();
for(int i=0;i< n;++i){
char c = s[i];
if(c>='0' && c<='9'){
int num = 0;
while(i<n && s[i]>='0' && s[i]<='9'){
num = 10*num + (s[i++] - '0');
}
res += sign*num;
i--;
}
else if(c=='+') sign = 1;
else if(c=='-') sign = -1;
else if(c=='('){
sta.push(res);
sta.push(sign);
res = 0;
sign = 1;
}
else if(c==')'){
res*= sta.top();sta.pop();
res+= sta.top(); sta.pop();
}
}
return res;
}
};
- time complexity
O(n)
- space complexity
O(n)