2240_NumberofWaystoBuyPensandPencils - a920604a/leetcode GitHub Wiki
title: 2240. Number of Ways to Buy Pens and Pencils
tags:
- Math
categories: leetcode
comments: false
solution
class Solution {
public:
long long waysToBuyPensPencils(int total, int cost1, int cost2) {
// cost1* x + cost2 * y <=total 所有解的個數
// option 1 brute force
// long long ret = 0;
// int n = total/cost1, m = total/cost2;
// for(int i=0;i<=n;++i){
// for(int j=0;j<=m;++j){
// if(i*cost1+j*cost2<=total) {
// ret++;
// }
// }
// }
// return ret;
// option 2 pruning
// long long ret = 0;
// int n = total/cost1, m = total/cost2;
// for(int i=0;i<=n;++i){
// int k =0;
// for(int j = m;j>-1;j--){
// if(cost1*i + cost2*j <=total){
// k = j;
// break;
// }
// }
// ret+= k+1;
// }
// return ret;
long long ret = 0;
if(total<cost1 && total <cost2){
return 1;
}
else if(total<cost1){
ret = (total/cost2) +1;
return ret;
}
else if(total<cost2){
ret = (total/cost1) +1;
return ret;
}
int val1 = max(cost1, cost2), val2 = min(cost1, cost2);
int n = total/val1;
// n 短邊
for(int i=0;i<=n;++i){
ret+= (total/val2)+1;
total-=val1;
}
return ret;
}
};
analysis
- time complecity
O(n)
- space complecity
O(1)