2119_ANumberAfteraDoubleReversal - a920604a/leetcode GitHub Wiki

---

title: 2119. A Number After a Double Reversal

tags:
- Bit Manipulation categories: leetcode comments: false

problem

solution

class Solution {
public:
    int reverse(int num){
        int ret = 0;
        while(num){
            ret*=10;
            ret+=(num%10);
            num/=10;
        }
        cout<<ret<<endl;
        return ret;
    }
    bool isSameAfterReversals(int num) {
        return reverse(reverse(num)) == num;
        
    }
};

analyze

• time complexity O(1)
• space complexity O(1)