title: 107. Binary Tree Level Order Traversal II
tags:
- bfs
categories: leetcode
comments: false
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
vector<vector<int>> levelOrderBottom(TreeNode* root) {
vector<vector<int>> ret;
if(!root) return ret;
queue<TreeNode*> q;
q.push(root);
while(!q.empty()){
int size = q.size();
vector<int> level;
for(int i=0;i<size;++i){
TreeNode * p = q.front();
q.pop();
level.push_back(p->val);
if(p->left) q.push(p->left);
if(p->right) q.push(p->right);
}
ret.push_back(level);
}
reverse(ret.begin(), ret.end());
return ret;
}
};
- time complexity
O(n)
- space complexity
O(n)