title: 102. Binary Tree Level Order Traversal
tags:
- bfs
categories: leetcode
comments: false
class Solution {
public:
vector<vector<int>> levelOrder(TreeNode* root) {
vector<vector<int>> ret;
if(!root) return ret;
queue<TreeNode *>q;
q.push(root);
while(!q.empty()){
int size = q.size();
vector<int> temp;
while(size-- >0){
TreeNode *p = q.front();
temp.push_back(p->val);
q.pop();
if(p->left) q.push(p->left);
if(p->right) q.push(p->right);
}
ret.push_back(temp);
}
return ret;
}
};
- time complexity
O(n)
- space complexity
O(n)