<script type="text/javascript" src="http://cdn.mathjax.org/mathjax/latest/MathJax.js?config=default"></script>
<script type="text/javascript" async src="https://cdn.mathjax.org/mathjax/latest/MathJax.js?config=TeX-MML-AM_CHTML"> </script>
$$\displaystyle T(n)\approx O(\frac{\sqrt{n}}{\log n})+T(\frac{6n}{\pi^2})=O(\frac{\sqrt{n}}{\log n})+T(\frac{n}{\tau})\$$
$$\displaystyle T(\tau^k)\approx O(\frac{\tau^{k/2}}{k\log \tau})+T(\tau^{k-1})=O(\frac{1}{\log \tau}\sum_{i=1}^{k}\frac{\tau^{i/2}}{i})$$
根据$$\displaystyle f(x)=\frac{a^x}{x},f'(x)=(\ln a-\frac{1}{x})\frac{a^x}{x}>0$$
$$\displaystyle 所以O(\frac{1}{\log \tau}\sum_{i=1}^{k}\frac{\tau^{i/2}}{i})\lt O(\frac{1}{\log \tau}k\frac{\tau^{k/2}}{k})=O(\frac{1}{\log \tau}\tau^{k/2})$$
$$\displaystyle n=\tau^k\Rightarrow k=\frac{\log n}{\log \tau}$$
$$\displaystyle \begin{aligned}T(n)=&T(\tau^k)=O(\frac{1}{\log \tau}\tau^{k/2})=O(\frac{1}{\log \tau}\tau^{\log n/(2\log\tau)})=O(\frac{1}{\log \tau}\mathrm{pow}(2,\frac{\log n\log \tau}{2\log \tau}))=O(\frac{\sqrt{n}}{\log \tau})=O(\sqrt{n})\end{aligned}$$
\(\displaystyle T(n)\approx O(\frac{\sqrt{n}}{\log n})+T(\frac{6n}{\pi^2})=O(\frac{\sqrt{n}}{\log n})+T(\frac{n}{\tau})\\)
