Mathematics functions - Leo-Corporation/LeoCorpLibrary GitHub Wiki

• Introduction
• Functions
• Maths
  • a. Sum
  • b. GetBiggestNumber
  • c. GetLowestNumber
  • d. RadiansToDegrees
  • e. DegreesToRadians

To uses these functios and features, do not forget to put this line of code on top of your code file:

C#

using LeoCorpLibrary;

VB

Imports LeoCorpLibrary

There is multiple functions availables in this part of LeoCorpLibrary.

This function is available in version 1.3 and higher

The Sum() method enables you to do a sum of double numbers.

It's in:

LeoCorpLibrary.Maths.Sum()

You need to specify the numbers which you wanna get the sum of, in the argument section of the method.

Note: You can specify negative numbers.

Here's an example of usage:

C#

double numberSum = Maths.Sum(0, 2, 5, 6, 4);

VB

Dim numberSum As Double = Maths.Sum(0, 2, 5, 6, 4)

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This function is available in version 1.3 and higher

The GetBiggestNumber() allows you to get the biggest number among double numbers that are specified. Returns a doublevalue.

It's in:

LeoCorpLibrary.Maths.GetBiggestNumber()

Note: You can use negative numbers

Here's an example of usage:

C#

double biggestNumber = Maths.GetBiggestNumber(0, 2, 3, 4, 5, 9, 8, 1);

VB

Dim biggestNumber As Double = Maths.GetBiggestNumber(0, 2, 3, 4, 5, 9, 8, 1)

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This function is available in version 1.3.1 and higher

The GetLowestNumber() method allows you to get the lowest number among double numbers that are specified. Returns a double value.

It's in:

LeoCorpLibrary.Maths.GetLowestNumber()

Note: You can use negative numbers.

Here's an example of usage:

C#

double lowestNumber = Maths.GetLowestNumber(0, 2, -1, 2.32);

VB

Dim lowestNumber As Double = Maths.GetLowestNumber(0, 2, -1, 2.32)

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This function is available in version 3.5 and higher

The RadiansToDegrees() method allows you to convert radians to degrees. Returns a double value.

It's in:

LeoCorpLibrary.Maths.RadiansToDegrees()

It has one argument:

Here's an example of usage:

C#

double degrees = Maths.RadiansToDegrees(1.57079633);
// Expected result: 90°

VB

Dim degrees As Double =  Maths.RadiansToDegrees(1.57079633)
' Expected result: 90°

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This function is available in version 3.5 and higher

The DegreesToRadians() method allows you to convert degrees to radians. Returns a double value.

It's in:

LeoCorpLibrary.Maths.DegreesToRadians()

It has one argument:

Here's an example of usage:

C#

double degrees = Maths.DegreesToRadians(90);
// Expected result: 1.57079633

VB

Dim degrees As Double =  Maths.DegreesToRadians(90)
' Expected result: 1.57079633

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This function is available in version 1.3 and higher

The GetArea() method allows you to get the area of circle. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Circle.GetArea()

This method has one argument:

Here's an example of usage:

C#

double circleArea = Maths.Circle.GetCircleArea(12.458);

VB

Dim circleArea As Double = Maths.Circle.GetCircleArea(12.458)

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This function is available in version 1.3 and higher

The GetPerimeter() allows you to get the perimeter of a circle. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Circle.GetPerimeter()

This method has one argument:

Here's an example of usage:

C#

double circlePerimeter = Maths.Circle.GetPerimeter(11.2);

VB

Dim circlePerimeter As Double = Maths.Circle.GetPerimeter(11.2)

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This function is available in version 3.2 and higher

The GetDiagonal() method allows you to get a rectangle's diagonal. It returns a double value.

It's in:

LeoCorpLibrary.Maths.Rectangle.GetDiagonal()

This method has two arguments:

Here's an example of usage:

C#

double diagonal = Maths.Rectangle.GetDiagonal(4.12, 8.5); // Get diagonal

VB

Dim diagonal As Double = Maths.Rectangle.GetDiagonal(4.12, 8.5) ' Get diagonal

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This function is available in version 1.3 and higher

The GetArea() method allows you to get the area of a triangle. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Triangle.GetArea()

This method has two arguments:

Here's an example of usage:

C#

double triangleArea = Maths.Triangle.GetArea(5.48, 4.12);

VB

Dim triangleArea As Double = Maths.Triangle.GetArea(5.48, 4.12)

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This function is available in version 1.3 and higher

The GetPerimeter() method allows you to get the perimeter of a triangle. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Triangle.GetPerimeter()

This method has three arguments:

Here's an example of usage:

C#

double trianglePerimeter = Maths.Triangle.GetPerimeter(5.48, 4.12, 6);

VB

Dim trianglePerimeter As Double = Maths.Triangle.GetPerimeter(5.48, 4.12, 6)

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This function is available in version 1.3 and higher

The IsBuildable() method allows you to know if the specified dimensions can build a triangle. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Triangle.IsBuildable()

This method has three arguments:

Here's an example of usage:

C#

bool isBuildable = Maths.Triangle.IsBuildable(4.5, 9.1, 12.45);

VB

Dim isBuildable As Bool = Maths.Triangle.IsBuildable(4.5, 9.1, 12.45)

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This function is available in version 3.2 and higher

The GetHypotenuse() method allows you to get a triangle's hypotenuse from the two other sides. (Pythagore) It returns a double value.

It's in:

LeoCorpLibrary.Maths.Triangle.GetHypotenuse()

This method has two arguments:

Here's an example of usage:

C#

double hypotenuse = Maths.Triangle.GetHypotenuse(4.5, 6.1); // Get the hypotenuse

VB

Dim hypotenuse As Double = Maths.Triangle.GetHypotenuse(4.5, 6.1) ' Get the hypotenuse

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This function is available in version 1.8 and higher

The GetVolume() method allows you to get the volume of a cube.

It's in:

LeoCorpLibrary.Maths.Cube.GetVolume()

This method has two variation:

Variante 1

GetVolume(double side, double height) {...}

Here's the arguments:

Variante 2

GetVolume(double side) {...}

Here's the arguments:

Here's an example of usage:

C#

// In the case of a rectangular prism
double volume = Maths.Cube.GetVolume(12, 14);

// In the case of a cube
double volumeCube = Maths.Cube.GetVolume(12);

VB

' In the case of a rectangular prism
Dim volume As Double = Maths.Cube.GetVolume(12, 14)

' In the case of a cube
Dim volumeCube As Double = Maths.Cube.GetVolume(12)

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This function is available in version 1.8.1 and higher

The GetEdge() method enables you to get the edge of a cube. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Cube.GetEdge()

It has one argument:

Here's an example of usage:

C#

double areaBase = Maths.Cube.GetEdge(31);

VB

Dim areaBase As Double = Maths.Cube.GetEdge(31)

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This function is available in version 1.8 and higher

The GetVolume() method enables you to get the volume of a cylinder. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Cylinder.GetVolume()

It has two arguments:

Here's an example of usage:

C#

// Get the volume of a cylinder
double volume = Maths.Cylinder.GetVolume(13, 5);

VB

' Get the volume of a cylinder
Dim volume As Double = Maths.Cylinder.GetVolume(13, 5)

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This function is available in version 1.8.1 and higher

The GetHeight() method enables you to get the height of a cylinder. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Cylinder.GetHeight()

It has two arguments:

Here's an example of usage:

C#

double height = Maths.Cylinder.GetHeight(5, 21);

VB

Dim height As Double = Maths.Cylinder.GetHeight(5, 21)

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This function is available in version 1.8.1 and higher

The GetBaseArea() method allows you to get the area of the base of a cylinder. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Cylinder.GetBaseArea()

It has two arguments:

Here's an example of usage:

C#

double baseArea = Maths.Cylinder.GetBaseArea(10);

VB

Dim baseArea As Double = Maths.Cylinder.GetBaseArea(10)

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This function is available in version 1.8 and higher

The GetVolume() method allows you to get the volume of a pyramid. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Pyramid.GetVolume()

It has three arguments:

Here's an example of usage:

C#

// Get the volume of a pyramid
double volume = Maths.Pyramid.GetVolume(13, 5, 15);

VB

' Get the volume of a pyramid
Dim volume As Double = Maths.Pyramid.GetVolume(13, 5, 15)

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This function is available in version 1.8.1 and higher

The GetHeight() method allows you to get the height of a pyramid. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Pyramid.GetHeight()

It has three arguments:

Here's an example of usage:

C#

double height = Maths.Pyramid.GetHeight(10, 10, 100).

VB

Dim height As Double = Maths.Pyramid.GetHeight(10, 10, 100)

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This function is available in version 1.8.1 and higher

The GetLenghtBase() allows you to get the length of the base of a pyramid. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Pyramid.GetLenghtBase()

It has two arguments:

Here's an example of usage:

C#

double lengthBase = Maths.Pyramid.GetLenghtBase(100, 10);

VB

Dim lengthBase As Double = Maths.Pyramid.GetLenghtBase(100, 10)

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This function is available in version 1.8.1 and higher

The GetWidthBase() allows you to get the width of the base of a pyramid. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Pyramid.GetWidthBase()

It has two arguments:

Here's an example of usage:

C#

double widthBase = Maths.Pyramid.GetWidthBase(100, 10);

VB

Dim widthBase As Double = Maths.Pyramid.GetWidthBase(100, 10)

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This function is available in version 3.2 and higher

The GetArea() method allows you to get the area of an hexagon from the length of it's side. It returns a double value.

It's in:

LeoCorpLibrary.Maths.Hexagon.GetArea()

It has one argument:

Here's an example of usage:

C#

double hexagonArea = Maths.Hexagon.GetArea(8); // Get the area

VB

Dim hexagonArea As Double = Maths.Hexagon.GetArea(8) ' Get the area

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This function is available in version 3.2 and higher

The GetPerimeter() method allows you to get the perimeter of a hexagon. It returns a double value.

It's in:

LeoCorpLibrary.Maths.Hexagon.GetPerimeter()

It has one argument:

Here's an example of usage:

C#

double hexagonPerimeter = Maths.Hexagon.GetPerimeter(7.2); // Get perimeter

VB

Dim hexagonPerimeter As Double = Maths.Hexagon.GetPerimeter(7.2) ' Get perimeter

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This function is available in version 3.2 and higher

The GetArea() method allows you to get the area of a diamond. It returns a double value.

It's in:

LeoCorpLibrary.Maths.Diamond.GetArea()

It has one argument:

Here's an example of usage:

C#

double diamondArea = Maths.Diamond.GetArea(4.5, 7.5); // Get area

VB

Dim diamondArea As Double = Maths.Diamond.GetArea(4.5, 7.5) ' Get area

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This function is available in version 3.2 and higher

The GetPerimeter() method allows you to get the area of a diamond. It returns a double value.

It's in:

LeoCorpLibrary.Maths.Diamond.GetPerimeter()

It has one argument:

Here's an example of usage:

C#

double diamondPerimeter = Maths.Diamond.GetPerimeter(8); // Get perimeter

VB

Dim diamondPerimeter As Double = Maths.Diamond.GetPerimeter(8) ' Get perimeter

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This function is available in version 3.8 and higher

The GetArea() method allows you to get the area of a sphere from its radius. It returns a double value.

It's in:

LeoCorpLibrary.Maths.Sphere.GetArea()

It has one argument:

Here's an example of usage:

C#

double area = Maths.Sphere.GetArea(10);
// Expected output:
// 1256.6370614359173

VB

Dim area As Double = Maths.Sphere.GetArea(10)
' Expected output:
' 1256.6370614359173

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This function is available in version 3.8 and higher

The GetVolume() method allows you to get the volume of a sphere from its radius. It returns a double value.

It's in:

LeoCorpLibrary.Maths.Sphere.GetVolume()

It has one argument:

Here's an example of usage:

C#

double volume = Maths.Sphere.GetVolume(10);
// Expected output:
// 4188.790204786391

VB

Dim volume As Double = Maths.Sphere.GetVolume(10)
' Expected output:
' 4188.790204786391

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This function is available in version 3.5 and higher

The GetTriangleOpposedSideFromHypotenuse() allows you to get a triangle's opposed side from an angle, and its hypotenuse. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Trigonometry.GetTriangleOpposedSideFromHypotenuse()

It has one argument:

Here's an example of usage:

C#

double opposedSide = Maths.Trigonometry.GetTriangleOpposedSideFromHypotenuse(1.05, 10);
// Expected result: 8.66
// Actual result: 8.67423225594017

VB

Dim opposedSide As Double = Maths.Trigonometry.GetTriangleOpposedSideFromHypotenuse(1.05, 10)
' Expected result: 8.66
' Actual result: 8.67423225594017

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This function is available in version 3.5 and higher

The GetTriangleOpposedSideFromAdjacent() method allows you to get a triangle's opposed side from an angle, and its adjacent side. It returns a double value.

It's in:

LeoCorpLibrary.Maths.Trigonometry.GetTriangleOpposedSideFromAdjacent()

It has one argument:

Here's an example of usage:

C#

double opposedSide = Maths.Trigonometry.GetTriangleOpposedSideFromAdjacent(1.05, 5);
// Expected result: 8.66
// Actual result: 8.716576549915851

VB

Dim opposedSide As Double = Maths.Trigonometry.GetTriangleOpposedSideFromAdjacent(1.05, 5)
' Expected result: 8.66
' Actual result: 8.716576549915851

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This function is available in version 3.5 and higher

The GetTriangleAdjacentSideFromHypotenuse() method allows you to get a triangle's adjacent side from an angle, and its hypotenuse. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Trigonometry.GetTriangleAdjacentSideFromHypotenuse()

It has one argument:

Here's an example of usage:

C#

double adjacentSide = Maths.Trigonometry.GetTriangleAdjacentSideFromHypotenuse(1.05, 10);
// Expected result: 5
// Actual result: 4.97571047891727

VB

Dim opposedSide As Double = Maths.Trigonometry.GetTriangleAdjacentSideFromHypotenuse(1.05, 10)
' Expected result: 5
' Actual result: 4.97571047891727

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This function is available in version 3.5 and higher

The GetTriangleAdjacentSideFromOpposedSide() method allows you to get a triangle's adjacent side from an angle, and its opposed side. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Trigonometry.GetTriangleAdjacentSideFromOpposedSide()

It has one argument:

Here's an example of usage:

C#

double adjacentSide = Maths.Trigonometry.GetTriangleAdjacentSideFromOpposedSide(1.05, 8.66);
// Expected result: 5
// Actual result: 4.967546576576329

VB

Dim adjacentSide As Double = Maths.Trigonometry.GetTriangleAdjacentSideFromOpposedSide(1.05, 8.66)
' Expected result: 5
' Actual result: 4.967546576576329

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This function is available in version 3.5 and higher

The GetTriangleHypotenuseFromOpposedSide() method allows you to get a triangle's hypotenuse from an angle, and its opposed side. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Trigonometry.GetTriangleHypotenuseFromOpposedSide()

It has one argument:

Here's an example of usage:

C#

double hypotenuse = Maths.Trigonometry.GetTriangleHypotenuseFromOpposedSide(1.05, 8.66);
// Expected result: 10
// Actual result: 9.98359248920223

VB

Dim hypotenuse As Double = Maths.Trigonometry.GetTriangleHypotenuseFromOpposedSide(1.05, 8.66)
' Expected result: 10
' Actual result: 9.98359248920223

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This function is available in version 3.5 and higher

The GetTriangleHypotenuseFromAdjacentSide() method allows you to get a triangle's hypotenuse from an angle, and its adjacent side. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Trigonometry.GetTriangleHypotenuseFromAdjacentSide()

It has one argument:

Here's an example of usage:

C#

double hypotenuse = Maths.Trigonometry.GetTriangleHypotenuseFromAdjacentSide(1.05, 5);
// Expected result: 10
// Actual result: 10.04881618652381

VB

Dim hypotenuse As Double = Maths.Trigonometry.GetTriangleHypotenuseFromAdjacentSide(1.05, 5)
' Expected result: 10
' Actual result: 10.04881618652381

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