What is the direction of the electric field at point [A]?

• Right

What is the direction of the electric field at point [B]?

• Left

In which of the two cases shown below is the magnitude of the electric field at the point labeled [A]

• The will be equal.

What is the direction of the electric field at point [P], the unoccupied corner of the square?

• (A) - Up and to the right.

  • [-q]

    • [r = \sqrt{ 2d^2}]
    • [\sqrt{ E_x_{-q}^2 + E_y_{-q}^2} = k \left(\frac{ q}{ 2d^2} \cos{ \frac{ \pi}{ 4}}\right) + k \left(\frac{ q}{ 2d^2} \sin{ \frac{ \pi}{ 4}} \right)]

  • [+q]s

    • [

  • The [-q] charge is [r = \sqrt{ 2d^2}] from [P] and acts on the point with a force of magnitude