Returns every nth element in the sequence.

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• Definition
• Overloads
• EveryNth(int n)

Returns every nth element in the sequence.

public static IEnumerable<T> EveryNth<T>(this IEnumerable<T> source, int n)

TSource
The type of the elements of source.

source IEnumerable <TSource>
The source sequence.

n Int32
The number of elements to skip before returning an element.

IEnumerable<TSource>
Every nth element in the sequence.

ArgumentNullException
source is null

ArgumentOutOfRangeException
n is less than or equal to zero

The following code example demonstrates how to use EveryNth(int n) to get every second element of the sequence.

int[] sequence = new int[] { 1, 2, 3, 4, 5, 6, 7 };

sequence.EveryNth(2);
//=> [ 2, 4, 6 ]