Introduction and Insertion (Doubly Linked List) - Dieptranivsr/DroneIVSR GitHub Wiki

A Doubly Linked List (DLL) contains an extra pointer, typically called previous pointer, together with next pointer and data which are there in singly linked list.

DLL1

Following is representation of a DLL node in C++ language.

/* Node of a doubly linked list */
class Node
{
	public:
	int data;
	Node* next; // Pointer to next node in DLL
	Node* prev; // Pointer to previous node in DLL
};

Following are advantages/disadvantages of doubly linked list over singly linked list.

Advantages over singly linked list

  1. A DLL can be traversed in both forward and backward direction.
  2. The delete operation in DLL is more efficient if pointer to the node to be deleted is given.
  3. We can quickly insert a new node before a given node. In singly linked list, to delete a node, pointer to the previous node is needed. To get this previous node, sometimes the list is traversed. In DLL, we can get the previous node using previous pointer.

Disadvantages over singly linked list

  1. Every node of DLL Require extra space for an previous pointer. It is possible to implement DLL with single pointer though (See this and this).
  2. All operations require an extra pointer previous to be maintained. For example, in insertion, we need to modify previous pointers together with next pointers. For example in following functions for insertions at different positions, we need 1 or 2 extra steps to set previous pointer.

Insertion

A node can be added in four ways

  1. At the front of the DLL
  2. After a given node.
  3. At the end of the DLL
  4. Before a given node.

1) Add a node at the front: (A 5 steps process)

The new node is always added before the head of the given Linked List. And newly added node becomes the new head of DLL. For example if the given Linked List is 10 15 20 25 and we add an item 5 at the front, then the Linked List becomes 5 10 15 20 25. Let us call the function that adds at the front of the list is push(). The push() must receive a pointer to the head pointer, because push must change the head pointer to point to the new node (See this) DLL_add_front1

/* Given a reference (pointer to pointer)
to the head of a list
and an int, inserts a new node on the
front of the list. */
void push(Node** head_ref, int new_data)
{
	/* 1. allocate node */
	Node* new_node = new Node();

	/* 2. put in the data */
	new_node->data = new_data;

	/* 3. Make next of new node as head
	and previous as NULL */
	new_node->next = (*head_ref);
	new_node->prev = NULL;

	/* 4. change prev of head node to new node */
	if ((*head_ref) != NULL)
		(*head_ref)->prev = new_node;
		
	/* 5. move the head to point to the new node */
	(*head_ref) = new_node;
}		

Four steps of the above five steps are same as the 4 steps used for inserting at the front in singly linked list. The only extra step is to change previous of head.

2) Add a node after a given node.: (A 7 steps process)

We are given pointer to a node as prev_node, and the new node is inserted after the given node. DLL_add_middle1

/* Given a node as prev_node, insert
a new node after the given node */
void insertAfter(Node* prev_node, int new_data)
{
	/*1. check if the given prev_node is NULL */
	if (prev_node == NULL)
	{
		cout<<"the given previous node cannot be NULL";
		return;
	}

	/* 2. allocate new node */
	Node* new_node = new Node();

	/* 3. put in the data */
	new_node->data = new_data;

	/* 4. Make next of new node as next of prev_node */
	new_node->next = prev_node->next;

	/* 5. Make the next of prev_node as new_node */
	prev_node->next = new_node;

	/* 6. Make prev_node as previous of new_node */
	new_node->prev = prev_node;

	/* 7. Change previous of new_node's next node */
	if (new_node->next != NULL)
		new_node->next->prev = new_node;
}

Five of the above steps step process are same as the 5 steps used for inserting after a given node in singly linked list. The two extra steps are needed to change previous pointer of new node and previous pointer of new node’s next node.

3) Add a node at the end: (7 steps process)

The new node is always added after the last node of the given Linked List. For example if the given DLL is 5 10 15 20 25 and we add an item 30 at the end, then the DLL becomes 5 10 15 20 25 30.

Since a Linked List is typically represented by the head of it, we have to traverse the list till end and then change the next of last node to new node. DLL_add_end1 Following are the 7 steps to add node at the end.

/* Given a reference (pointer to pointer) to the head
of a DLL and an int, appends a new node at the end */
void append(Node** head_ref, int new_data)
{
	/* 1. allocate node */
	Node* new_node = new Node();

	Node* last = *head_ref; /* used in step 5*/

	/* 2. put in the data */
	new_node->data = new_data;

	/* 3. This new node is going to be the last node, so
		make next of it as NULL*/
	new_node->next = NULL;

	/* 4. If the Linked List is empty, then make the new
		node as head */
	if (*head_ref == NULL)
	{
		new_node->prev = NULL;
		*head_ref = new_node;
		return;
	}

	/* 5. Else traverse till the last node */
	while (last->next != NULL)
		last = last->next;

	/* 6. Change the next of last node */
	last->next = new_node;

	/* 7. Make last node as previous of new node */
	new_node->prev = last;

	return;
}

Six of the above 7 steps are same as the 6 steps used for inserting after a given node in singly linked list. The one extra step is needed to change previous pointer of new node.

4) Add a node before a given node:

Steps

Let the pointer to this given node be next_node and the data of the new node to be added as new_data.

  1. Check if the next_node is NULL or not. If it's NULL, return from the function because any new node can not be added before a NULL
  2. Allocate memory for the new node, let it be called new_node
  3. Set new_node->data = new_data
  4. Set the previous pointer of this new_node as the previous node of the next_node, new_node->prev = next_node->prev
  5. Set the previous pointer of the next_node as the new_node, next_node->prev = new_node
  6. Set the next pointer of this new_node as the next_node, new_node->next = next_node;
  7. If the previous node of the new_node is not NULL, then set the next pointer of this previous node as new_node, new_node->prev->next = new_node
  8. Else, if the prev of new_node is NULL, it will be the new head node. So, make (*head_ref) = new_node.

5-55-300x100

Below is the implementation of the above approach:

// A complete working C++ program to demonstrate all
// insertion before a given node
#include <iostream>
using namespace std;

// A linked list node
struct Node {
	int data;
	struct Node* next;
	struct Node* prev;
};

/* Given a reference (pointer to pointer) to the head of a
list and an int, inserts a new node on the front of the
list. */
void push(struct Node** head_ref, int new_data)
{
	struct Node* new_node
		= (struct Node*)malloc(sizeof(struct Node));

	new_node->data = new_data;

	new_node->next = (*head_ref);
	new_node->prev = NULL;

	if ((*head_ref) != NULL)
		(*head_ref)->prev = new_node;

	(*head_ref) = new_node;
}

/* Given a node as next_node, insert a new node before the
* given node */
void insertBefore(struct Node** head_ref, struct Node* next_node, int new_data)
{
	/*1. check if the given next_node is NULL */
	if (next_node == NULL) {
		cout <<"the given next node cannot be NULL";
		return;
	}

	/* 2. allocate new node */
	struct Node* new_node
		= (struct Node*)malloc(sizeof(struct Node));

	/* 3. put in the data */
	new_node->data = new_data;

	/* 4. Make prev of new node as prev of next_node */
	new_node->prev = next_node->prev;

	/* 5. Make the prev of next_node as new_node */
	next_node->prev = new_node;

	/* 6. Make next_node as next of new_node */
	new_node->next = next_node;

	/* 7. Change next of new_node's previous node */
	if (new_node->prev != NULL)
		new_node->prev->next = new_node;
	/* 8. If the prev of new_node is NULL, it will be
	the new head node */
	else
		(*head_ref) = new_node;
}

// This function prints contents of linked list starting
// from the given node
void printList(struct Node* node)
{
	struct Node* last;
	cout <<"\nTraversal in forward direction \n";
	while (node != NULL) {
		cout <<" "<< node->data;
		last = node;
		node = node->next;
	}

	cout <<"\nTraversal in reverse direction \n";
	while (last != NULL) {
		cout <<" "<< last->data;
		last = last->prev;
	}
}

/* Driver program to test above functions*/
int main()
{
	/* Start with the empty list */
	struct Node* head = NULL;
	push(&head, 7);

	push(&head, 1);

	push(&head, 4);

	// Insert 8, before 1. So linked list becomes
	// 4->8->1->7->NULL
	insertBefore(&head, head->next, 8);

	cout <<"Created DLL is: ";
	printList(head);

	getchar();
	return 0;
}

Output:

  Created DLL is:
  Traversal in forward Direction
   9 1 5 7 6
  Traversal in reverse direction
   6 7 5 1 9 

A complete working program to test above functions.

Following is complete program to test above functions.

// A complete working C++ program to
// demonstrate all insertion methods
#include <bits/stdc++.h>
using namespace std;

// A linked list node
class Node
{
	public:
	int data;
	Node* next;
	Node* prev;
};

/* Given a reference (pointer to pointer)
to the head of a list
and an int, inserts a new node on the
front of the list. */
void push(Node** head_ref, int new_data)
{
	/* 1. allocate node */
	Node* new_node = new Node();

	/* 2. put in the data */
	new_node->data = new_data;

	/* 3. Make next of new node as head
	and previous as NULL */
	new_node->next = (*head_ref);
	new_node->prev = NULL;

	/* 4. change prev of head node to new node */
	if ((*head_ref) != NULL)
		(*head_ref)->prev = new_node;

	/* 5. move the head to point to the new node */
	(*head_ref) = new_node;
}

/* Given a node as prev_node, insert
a new node after the given node */
void insertAfter(Node* prev_node, int new_data)
{
	/*1. check if the given prev_node is NULL */
	if (prev_node == NULL)
	{
		cout<<"the given previous node cannot be NULL";
		return;
	}

	/* 2. allocate new node */
	Node* new_node = new Node();

	/* 3. put in the data */
	new_node->data = new_data;

	/* 4. Make next of new node as next of prev_node */
	new_node->next = prev_node->next;

	/* 5. Make the next of prev_node as new_node */
	prev_node->next = new_node;

	/* 6. Make prev_node as previous of new_node */
	new_node->prev = prev_node;

	/* 7. Change previous of new_node's next node */
	if (new_node->next != NULL)
		new_node->next->prev = new_node;
}

/* Given a reference (pointer to pointer) to the head
of a DLL and an int, appends a new node at the end */
void append(Node** head_ref, int new_data)
{
	/* 1. allocate node */
	Node* new_node = new Node();

	Node* last = *head_ref; /* used in step 5*/

	/* 2. put in the data */
	new_node->data = new_data;

	/* 3. This new node is going to be the last node, so
		make next of it as NULL*/
	new_node->next = NULL;

	/* 4. If the Linked List is empty, then make the new
		node as head */
	if (*head_ref == NULL)
	{
		new_node->prev = NULL;
		*head_ref = new_node;
		return;
	}

	/* 5. Else traverse till the last node */
	while (last->next != NULL)
		last = last->next;

	/* 6. Change the next of last node */
	last->next = new_node;

	/* 7. Make last node as previous of new node */
	new_node->prev = last;

	return;
}

// This function prints contents of
// linked list starting from the given node
void printList(Node* node)
{
	Node* last;
	cout<<"\nTraversal in forward direction \n";
	while (node != NULL)
	{
		cout<<" "<<node->data<<" ";
		last = node;
		node = node->next;
	}

	cout<<"\nTraversal in reverse direction \n";
	while (last != NULL)
	{
		cout<<" "<<last->data<<" ";
		last = last->prev;
	}
}

/* Driver program to test above functions*/
int main()
{
	/* Start with the empty list */
	Node* head = NULL;

	// Insert 6. So linked list becomes 6->NULL
	append(&head, 6);

	// Insert 7 at the beginning. So
	// linked list becomes 7->6->NULL
	push(&head, 7);

	// Insert 1 at the beginning. So
	// linked list becomes 1->7->6->NULL
	push(&head, 1);

	// Insert 4 at the end. So linked
	// list becomes 1->7->6->4->NULL
	append(&head, 4);

	// Insert 8, after 7. So linked
	// list becomes 1->7->8->6->4->NULL
	insertAfter(head->next, 8);

	cout << "Created DLL is: ";
	printList(head);

	return 0;
}

Output:

  Created DLL is: 
  Traversal in forward Direction
   1 7 5 8 6 4 
  Traversal in reverse direction
   4 6 8 5 7 1 
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