CYLINDER 1:

height of cylinder = h= 10cm

radius of cylinder = r = 1.5cm

density of cylinder = ρ =1.185

Volume of cylinder= πr²h = 3.142 * r^2 * h = 3.142 * 10 * 1.5^2 = 70.695 cm³

Mass (m) = Volume × Density =70..695* 1.185 =83.7735 g

MAX load weight it should handle=2.5 kg

Radius (from shaft to the load)= 1.5 cm

Safety factor =1.5

Torque= (2..5)(1.5)(1.5)= 6.75 kg-cm

Therefore ,the apt motor would be a dc motor of 3.5 RPM

CYLINDER 2:

height of cylinder = h= 10cm

radius of cylinder = r = 1.5cm

density of cylinder = ρ =1.185

Volume of cylinder= πr²h = 3.142 * r^2 * h = 3.142 * 10 * 1.5^2 = 70.695 cm³

Mass (m) = Volume × Density =70..695* 1.185 =83.7735 g

MAX load weight it should handle=2.5 kg

Radius (from shaft to the load)= 1.5 cm

Safety factor =1.5

Torque= (2..5)(1.5)(1.5)= 6.75 kg-cm

Therefore ,the apt motor would be a dc motor of 3.5 RPM

MECHANISM:

· Radius r=0.05 m

· Thickness h=0.002 m

· Density ρ=1185 kg/m3

V=πr2h=π⋅(0.05)2⋅0.002=1.571×10−5m3=15.71cm3

m=ρ⋅V=1185⋅1.571×10−5≈0.0186kg=18.6g

MAX load weight it should handle=2.5kg

Radius (from shaft to the load)= 1.5 cm

Safety factor =1.5

Torque= (2..5)(1.5)(1.5)= 6.75 kg-cm

Therefore ,the apt motor would be a dc motor of 3.5 RPM

ADAPTER SELECTION:

POWER VALUE =2 * 5^* 1.2 = 12V

BASED ON THE POWER VALUE CALCULATIONS A 12V-2A ADAPTER IS SUITABLE TO RUN THE MOTORS.